WHomework set 4_solns_2011

WHomework set 4_solns_2011 - Homework set # 4 Problems:...

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Homework set # 4 Problems: 16.17, 20 - 23 Solutions: 16.17 From conservation of energy,     ee f i KE PE KE PE  , which gives 2 1 00 2 e i f kQq mv r or    22 27 92 2 e e f ii ke e r    2 2 91 9 2 14 2 27 7 Nm 2 8.99 10 158 1.60 10 C C 2.74 10 m 6.64 10 kg 2.00 10 m s f r     16.20 (a)      66 4.00 10 F 12.0 V 48.0 10 C 48.0 C QCV   (b)      4.00 10 F 1.50 V 6.00 10 C 6.00 C 16.21 (a)   62 2 12 8 0 2 1.0 10 m C 8.85 10 1.1 10 F N m 800 m A C d  (b)     86 1.11 10 F 3.0 10 N C 800 m 27 C max max max QC V C E d   16.22 For a parallel plate capacitor, QQQ d V CA dA    . (a) Doubling d while holding Q and A constant doubles V to 800 V . (b)   0 AV Q d  Thus, doubling
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This note was uploaded on 05/12/2011 for the course PHYS 1112 taught by Professor Seaton during the Spring '08 term at University of Georgia Athens.

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WHomework set 4_solns_2011 - Homework set # 4 Problems:...

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