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Homework set # 9
Problems: 19.20, 22; 20.1, 3
Solutions:
19.20
The magnitude of the torque is
sin
NBIA
, where
is the angle between the
field and the perpendicular to the plane of the loop. The circumference of the
loop is
22
.
0
0
m
r
, so the radius is
1.00 m
r
and the area is
1
m
Ar
.
Thus,
32
3
1
1 0.800 T 17.0 10 A
m
sin90.0
4.33 10 N m
19.22
Note that the angle between the field and the perpendicular to the plane of the
loop is
90.0
30.0
60.0
. Then, the magnitude of the torque is
sin
100 0.80 T 1.2 A
0.40 m
0.30 m
sin60.0
10 N m
NBIA
With current in the –
y
direction, the outside edge of the loop will experience a
force directed out of the page (+
z
direction) according to the right hand rule.
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 Spring '08
 SEATON
 Work

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