Homework set # 9 Problems: 19.20, 22; 20.1, 3 Solutions: 19.20The magnitude of the torque is sinNBIA, where is the angle between the field and the perpendicular to the plane of the loop. The circumference of the loop is 22.00mr, so the radius is 1.00 mrand the area is 1mAr. Thus, 32311 0.800 T 17.0 10 Amsin90.04.33 10 N m19.22Note that the angle between the field and the perpendicular to the plane of the loop is 90.030.060.0. Then, the magnitude of the torque is sin100 0.80 T 1.2 A0.40 m0.30 msin60.010 N mNBIAWith current in the –ydirection, the outside edge of the loop will experience a force directed out of the page (+zdirection) according to the right hand rule.
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