1.5 notes - An extraneous solution is a solution of an...

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1.5 Notes: Absolute Value Equations and Inequalities Warm-up Solve each equation. 1) 5(x – 6) = 40 2) 2y + 6y = 15 – 2y + 8 3) 4x + 8 > 20 4) 4(t – 1) < 3t + 5 Objective: - solve absolute value equations -solve absolute value inequalities The absolute value of a number is its distance from zero on a number line and distance in non-negative. If x 0, then |x| = 0 If x < 0, then |x| = - x Solving Absolute Value Equations 1) | 2y – 4 | = 12 SO…. 2y – 4 = ? So there are two equations to consider 1) or 2) 2) | 3x + 2 | = 7 3) 3 | 4w – 1 | - 5 = 10
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Unformatted text preview: An extraneous solution is a solution of an equation derived from an original equation that is not a solution of the original equation Checking for Extraneous Solutions 1) | 2x + 5 | = 3x + 4 2) | 2x + 3 | = 3x + 2 Absolute Value Inequalities Graph |x| &gt; 3 Solve and graph. 1) | 3x + 6 | 12 3x + 6 could be two things Step 1: Drop absolute value symbol and solve Step 2: Drop absolute value symbol, flip inequality, and make 12 negative. 2) 3| 2x + 6 | - 9 &lt; 15 You try 3) | 5z + 3 | - 7 &lt; 34...
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This note was uploaded on 05/13/2011 for the course MTH 98 taught by Professor Johnson during the Fall '09 term at Grand Valley State University.

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1.5 notes - An extraneous solution is a solution of an...

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