366lab5 - 2. dP/dt = r dP = rdt P = rt + c P(0) = c = 379...

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Unformatted text preview: 2. dP/dt = r dP = rdt P = rt + c P(0) = c = 379 P(1) = r + c = r + 379 = 423 r = 44 P(t) = 44t + 379 P(23) = 44*23+379 = 1391 3. dP/dt = rP dP/P = rdt ln(P) = r t + c P = e^(rt+c) = ce^(rt) P(0) = c = 379 P(1) = 379e^r = 423 r = 0.11 P(t) = 379e^0.11t P(23) = 379e^2.53 = 4759 4. r = ln(6016(2239-379)/379(6016-2239))/10 = ln(11189760/1431483)/10 = 0.2 K = 379*2239*(1-e^-2)/(379-2239e^-2) = 733734/76 = 7994 P(t) = 3029726/(379 + 7615e^-0.2t) P(23) = 3029726/455 = 6658 5. 7000 6000 5000 4000 3000 2000 1000 0 0 2 4 6 8 10 12 14 16 18 20 C is the most accurate. 6. A norm(A-Q,1)/20 = 1.9762e+003 B norm(A-B,1)/20 = 1.3577e+003 C norm(A-C,1)/20 = 262.5403 7. I used MAPLE and found P=738*exp(0.2988*t); When t<0, the predict value < data When t>0, the predict value > data P(20) = 10190 8. ...
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This note was uploaded on 05/15/2011 for the course MA 366 taught by Professor Cho during the Spring '08 term at Purdue University-West Lafayette.

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366lab5 - 2. dP/dt = r dP = rdt P = rt + c P(0) = c = 379...

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