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Unformatted text preview: H rxn , S rxn , and G rxn at 298 K. Since this reaction is not spontaneous, how can it occur? 4. Calculate G rxn for the following reaction using the two reactions (and their G rxn ) below. CaCO 3 ( s ) CaO ( s ) + CO 2 ( g ) Ca ( s ) + CO 2 ( g ) + O 2 ( g ) CaCO 3 ( s ) G rxn = -734.4 kJ 2 Ca ( s ) + O 2 ( g ) 2 CaO ( s ) G rxn = -1206.6 kJ 6. Calculate G rxn for the following reaction at 298 K where the partial pressures were not all 1 atm, but rather the conditions listed below. CO 2 ( g ) + CCl 4 ( g ) 2 COCl 2 ( g ) P CO 2 = 0.112 atm P CCl 4 = 0.174 atm P COCl 2 = 0.774 atm 7. Consider the following reaction: I 2 ( g ) + Cl 2 ( g ) 2 ICl ( g ) K p = 81.9 at 298 K 8. Calculate G rxn for the reaction at 298 K under each of the following conditions: a) at standard conditions b) at equilibrium c) P I 2 = 0.325 atm P Cl 2 = 0.221 atm P ICl = 2.55 atm...
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This note was uploaded on 05/15/2011 for the course CHM 116 taught by Professor Matchett during the Fall '11 term at Grand Valley State University.
- Fall '11