Hw5_sol - Hw5 Solution 1 4 2 0-2 residual-4-6-8-10 0.6 0.61...

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Hw5 Solution 1. 0.6 0.61 0.62 0.63 0.64 0.65 0.66 0.67 0.68 -10 -8 -6 -4 -2 0 2 4 VD (V) residual From the plot, VD=0.645V, ( ) 1 / 0 = kT qV D D e I I = 0.594mA VDD=5; Is=1e-14;R=8e3;VT=0.026; Vd=0.6:1e-3:0.67 f=VDD-Is*(exp(Vd/VT)-1)*R-Vd; plot(Vd,f,Vd,zeros(1,length(Vd))); xlabel( 'VD (V)' ); ylabel( 'residual' )

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2. 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 -5 0 5 10 15 20 25 V(Volt) I(mA) 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 -5 0 5 10 15 20 25 X: 1.617 Y: 0.4229 V(Volt)
ID=0.423mA VD=1.617V %Diode IV from Ctools I=[…]; V=[…]; VDD=5;R=8; IR= (VDD-V)/R; plot(V,I); xlabel( 'V(Volt)' ); ylabel( 'I(mA)' ); figure; plot(V,I,V,IR);xlabel( 'V(Volt)' ); ylabel( 'I(mA)' );

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4. 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 x 10 -3 X: 4. 5 Y: 0.0001 VDS(V) ID (A) VGS=2V VGS=2.5V VGS=3V VGS=3.5V VGS=4V VGS=4.5V VGS=5V From the figure, when Vin=VGS=2V=> Vout=VDS=4.5V VT=1.1;k=0.25e-3; RL=5e3;VDD=5; VDS= 0:0.1:5; VGS=0:0.5:5; VGS=VGS'; VDS=repmat(VDS,size(VGS,1),1); VGS=repmat(VGS,1,size(VDS,2));

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This homework help was uploaded on 04/04/2008 for the course EECS 215 taught by Professor Phillips during the Winter '08 term at University of Michigan.

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Hw5_sol - Hw5 Solution 1 4 2 0-2 residual-4-6-8-10 0.6 0.61...

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