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HW 5_1 - ME 3 4‘ HW 5 ~$oluhom.L(M 3m(x q l 0~ m d"...

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Unformatted text preview: ME 3!? 4‘ HW 5 ~$oluhom. ..L.. (M 3m (x: q . l 0~ m d" I \fepHm a»? \vxevmkc a 94 A Do 8' P330 L MD \m is “Ne/A . 4 0t} 3. S i w / 7 2. 29 Determine the reaction forces at the hin ge 0 if 0 wx O the bar (mass m) 18 released from rest at 6: 55 degrees ”x RQA (“5% H w .Vdouflfi MW “”3 0 : Mama L: 5:39 /KD. K D m- “1%“ A” I . y Ta: LW‘" “3:2 I; wife; t No L _ (MM mshmx‘r a? (mt/V135? :9 (If: '.€k= ”Kg (U: L/LDC =1) "U “ L/le 'ENZ “lg , near 504 aw‘w‘“ _ k\ 13%. _ ‘3 W ¥g D - ‘3 L H (Ts)351 kg) Such: +\M C : W‘fu : w—Q“ ML MW‘W .o< t R1- (3 K H . 2. tqagflflfwmm WM“ RT" ‘MCK‘ Mi“ 4 who @ u ' .. -T 2M6} Rafi/L) - ,’ (X ac , ‘- A- W Ti“ 21‘ L/ “- ML - 2., RT + Nat“ 7-< i, "> L —'-\M Cx A -‘M“C.5 -’ - (A LA) Ar. Ia _ M'L-LZLL RT: ‘06”) :-—o LOLfiLmfi (Awsj 1% M K” § \ a? when»: L We Q We ‘MWM- ' .‘RM— w‘ggx : Ov‘grfieui) (ANS) T;~2'57‘6‘ —- “Ach 1'. Not}: M VOWWNM) Ag) Mwm‘gj CW [5L rwt’ng W3. ~ M” .5 0‘ ‘ " ' _,. 19m: M t°f’*@3 .iM0.: (2)9 .ieH , ,, Ms C7095 My wwwMJ VFW 215:; w 5:99 ,(gF AFB} ‘h/ .V _ .4 l\ I . y, t. V 23F {m k9. FVGM 5:955) k~ " 'é'MO A ' g ' .- _._ , . ,_ 5/“ng (I; > : -:O;<\ :5 rodeBZ EIE L w :0: .Lwnj' M-(FE—4'0 ‘ + 745$: 2%“ NP 1*: ”AWL. a ’D I '3— » NW gyggo 5?) (X _ 90 ’gl V 1%? 3 “:35 M _ "93—. 3540915 _. 36C“; < L3r 2' ’2..L.. .A 3 K a? \V\ $931) > i? V‘ Km} >~ » —- . _ _7 ‘ _ L. M e. RT+MSC9< “AV" ”1’ Nfie Tn Mahaéd 2) Ni r.— "maraql We use, hm. RH S 0&@ which {5%va hm, 9mm and; Movm ’ 7 ~ 2 Z 5\ r We ' ., g ‘ V / 7.2.29. Determine the reaction forces at the hinge 0 if ,v AS‘SU M E, 'hA L ’W'0 h M YO be, a“ m M W 51"W\ o g; the bar (mass m) is released from rest at 6 = 55 degrees .ch‘mea— a? 9 a5 (/1 l x J ‘ \Wcm\-Lo\ . $45k “Aug/Y» MY) WWLBM , MW m fiwh‘ ’ “ML WNW 9 Lo V M Pod/M of W ©‘ {ng14, I .._ c€7§i‘¢\¢A—.=o* PMHA amid/NM‘K: "11‘" ‘1 "if? “Vii-2’ __ . [ Va ' ' ‘ §9(*Ig)-=wg) e . m 7). .. . L . 1-"; My : . '28 3 ”Sf-”(5‘3 “(3%? )W‘} L/Z 2 Iii; (K728? l‘i‘yé’ (x. é : —-&>{@Is>. “Q ’57"? 9S9 ‘ ’ - [_ ____ ,4?" wagsg + 93$ —— W38 é) _. ' ;L. ‘MSSG + £13 ‘ Mg: 1(213) _ ' 1:9 ’——~ “.3 R _ 5 Lt" =‘1s -/1..-3(z -:-—-—-."""'""'"-" X - R \ “at f Mflsg’ “'5 ' w 931 — W339», flow—m5 was) .90? 97:3“ ’5 __.. Z “r. K gmfl Ca 2:. O. (S:W‘«43’§l’bw 55 I Y‘Léb 3 R3 :2 NSCB‘ .7. 0.533; m‘fl- (ANS)«° ; 5 Mum 9:5; ' - we: 'RMMLW; lz'z‘) : {233(VMama-zgzo‘mae M3 QJMLMGM lg 2.); —@Is( {\A’gwodg) 2 —-o.zotfl- “4%- 90) W0 MKH’L‘K Whig/M Lova/xh'avx 3 gm “Sc. [35ml m,‘ 0W5\<, WM$ CuS—L.) <\‘o §0Y\NVU.\:LL)§L Hwy SMWWMJ a: J‘ lows k5 be» We, Lows-('sa‘coxi’f: gm wa ewci “‘10 ““th 1 “ 'PWaHALt/A YESM'H”;‘ I“ OWLM WWAS J "‘ A” A .31"; \56‘“ 0L§SUVMQ hn‘c mafia“ {\A 6‘ (’{vhm'vx (QU‘CQHCM) $3imcL 1 WWW Nov? Awahw‘ “HA/V?— Wkfl Wvovfl‘n hAZ/réolwhw (9n) ' fiawx‘e“ $165 355an ' 7.3.2. A uniform cylindrical body is connected to the ceil- ing by means of a linear spring with spring constant k and P \ ‘P § { A 6C1 W M (bl; ,4 g f through a massless rope that’s wrapped around the body and I d ‘ i that attaches to the Ceiling at A. Assume'that the spring is t‘ ' stretched 0.2 ft from its rest length in the position shown. ‘ The cylinder has a weight of 15 lb, a radius of 0.5 ft, and l k = 10 lb/ft. Upon release, what is the angular acceleration i‘ of the cylinder? ASSUMQ‘. W Cnldmm. E7$l2 swig t5 5&me dezk‘x ' 1V v 7'7 @[' 5‘31 ,3 :-‘* i» (A, X V 72’: Pa" Ve “Y9 = am 75‘“: '1: thhxo —Ji \l :%; r] fi:—V ‘ lk) .C'Y,t§ “Suki . ‘ -_—. ‘ _ ( G‘s/31“” t #1 2. 3mm? "8) X143) — "' VBLE) $155. 35500 /'\, M ,_.1> E 11 W, e ‘3 EM 11‘ 44> E F U _3L3~1» Amh7{_ _ _ ‘Novc Wu»? So §Wl ’WUL WMWMHCS th‘LM h) M (9% WV-LVL ‘Wl/Lce’,\ Vng cm W grow/J ._ ' 1/ 3+sz o& M swab 2” v>‘—- ’0 a “’L‘ .‘E : :W' Wzfl. _ . V V. . 32¢,— rrmi gfiésmw; ‘ H . j a” ,. *HTY.‘ :: féé" =1). . T :VI—EFE ”—6) .. a r45? \lw‘gm : 057—3}? ...
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