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(a) Along the
x
axis, we have (with the centimeter unit understood)
30.0
20.0
80.0
140,
x
b
+−
−
=
−
which gives
b
x
= –70.0 cm.
(b)
Along
the
y
axis we have
40.0
70.0
20.0
y
c
−+
−=
−
which yields
c
y
= 80.0 cm.
(c) The magnitude of the final location (–140 , –20.0) is
22
( 140)
( 20.0)
141 cm.
−
=
(d) Since the displacement is in the third quadrant, the angle of the overall displacement
is given by
π
+
1
tan [( 20.0)/( 140)]
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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