The equation relating these is ABCD+=+GG, where ˆˆ(1.60 m)(cos50.0 i sin50.0 j) (1.03 m)i (1.23 m)jC=°+°=+G(a) We find (0.16 m)i ( 0.83 m)jDABC=+−=+−, and the magnitude is D= 0.84 m. (b) The angle is 1tan ( 0.83/0.16)79−−=−°which is interpreted to mean 79º south of east (or 11º east of south). 24. Let A→represent the first part of Beetle 1’s trip (0.50 m east or
This is the end of the preview. Sign up
access the rest of the document.