(c) If the starting point is (0, a, 0) with the corresponding position vector ˆja, the diametrically opposite point is (a, 0, a) with the position vectorˆˆikaa+. Thus, the vector along the line is the difference ˆijka−+.(d) If the starting point is (a,a, 0) with the corresponding position vector i j+, the diametrically opposite point is (0, 0, a) with the position vectorˆka. Thus, the vector along the line is the difference ˆka−−+.(e) Consider the vector from the back lower left corner to the front upper right corner. It isˆj k.aaa++We may think of it as the sum of the vector a#iparallel to the xaxis and the vector j k##+perpendicular to the xaxis. The tangent of the angle between the vector and the xaxis is the perpendicular component divided by the parallel component. Since the magnitude of the perpendicular component is 222a+=and the magnitude of the parallel component is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.