We therefore obtain
22
(3.0)(2.0)
(5.0)(4.0)
ˆ
5.8.
(2.0)
(4.0)
b
aa
b
+
=⋅=
=
+
G
36. We apply Eq. 330 and Eq. 323.
(a)
ˆ
= (
) k
xy
yx
ab a
b ab
×−
G
G
since all other terms vanish, due to the fact that neither
G
a
nor
G
b
have any
z
components. Consequently, we obtain
ˆˆ
[(3.0)(4.0) (5.0)(2.0)]k
2.0k
−=
.
(b)
=
x
y
ab ab ab
⋅+
G
yields (3.0)(2.0) + (5.0)(4.0) = 26.
(c)
(3.0
2.0) i
(5.0
4.0) j
ab
+=
+
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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