37. Examining the figure, we see that a→+ b→c→= 0, where a→⊥b→. (a)|a→×b→| = (3.0)(4.0) = 12 since the angle between them is 90º. (b) Using the Right Hand Rule, the vector ab×GGpoints in the ˆˆ ˆijk×=, or the +zdirection.(c) | a→×c→| = | a→×(−a→−b→)| = | − (a→×b→)| =12.(d) The vector
This is the end of the preview. Sign up
access the rest of the document.