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22
1
2
(2.04 m)
(4.01 m)
4.50 m
(1.21 m)
(0.70 m)
1.40 m.
d
d
=+
=
=
Thus, the angle between the two vectors is
2
11
12
2.81 m
cos
cos
63.5 .
(4.50 m)(1.40 m)
dd
θ
−−
§·
⋅
==
=
°
¨¸
©¹
GG
38. The displacement vectors can be written as (in meters)
1
2
ˆˆ
ˆ
ˆ
(4.50 m)(cos63 j sin 63 k)
(2.04 m) j (4.01 m)k
ˆ
ˆ
(1.40 m)(cos30 i sin30 k)
(1.21 m)i (0.70 m)k .
d
d
=°
+
°
=
+
+
°
=
+
G
G
(a) The dot product of
1
d
G
and
2
d
G
is
2
ˆ
ˆ
(2.04 j 4.01k) (1.21i 0.70k) = (4.01k) (0.70k) = 2.81 m .
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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