ch03-p038 - 38. The displacement vectors can be written as...

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22 1 2 (2.04 m) (4.01 m) 4.50 m (1.21 m) (0.70 m) 1.40 m. d d =+ = = Thus, the angle between the two vectors is 2 11 12 2.81 m cos cos 63.5 . (4.50 m)(1.40 m) dd θ −− §· == = ° ¨¸ ©¹ GG 38. The displacement vectors can be written as (in meters) 1 2 ˆˆ ˆ ˆ (4.50 m)(cos63 j sin 63 k) (2.04 m) j (4.01 m)k ˆ ˆ (1.40 m)(cos30 i sin30 k) (1.21 m)i (0.70 m)k . d d + ° = + + ° = + G G (a) The dot product of 1 d G and 2 d G is 2 ˆ ˆ (2.04 j 4.01k) (1.21i 0.70k) = (4.01k) (0.70k) = 2.81 m .
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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