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cos
(3.2)(0.50) (1.6)(4.5)
(3.58)(4.53) cos
xx
yy
ab ab ab ab
φ
⋅
=+=
+=
G
G
which leads to
= 57° (the inverse cosine is doublevalued as is the inverse tangent, but
we know this is the right solution since both vectors are in the same quadrant).
(b) Since the angle (measured from +
x
) for
G
a
is tan
–1
(1.6/3.2) = 26.6°, we know the
angle for
G
c
is 26.6° –90° = –63.4° (the other possibility, 26.6° + 90° would lead to a
c
x
<
0). Therefore,
c
x
=
c
cos (–63.4° )= (5.0)(0.45) = 2.2 m.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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