ch03-p048 - 48. The vectors are shown on the diagram. The x...

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= 0 + 3.28 m = 3.28 m yy y cab =+ . The magnitude of c is () 22 2.71m 3.28m 4.2 m. xy ccc = + = (b) The angle θ that G G G makes with the + x axis is 11 3.28 tan tan 50 . 2.71 y x c c −− §· == = ° ¨¸ ©¹ The second possibility ( = 50.4° + 180° = 230.4°) is rejected because it would point in a direction opposite to G c . (c) The vector ba G G is found by adding G G ab to . The result is shown on the diagram to the right. Let . cba =− G GG The components are 2.29 m 5.00 m 7.29 m, xxx =−= = and 3.28 m. yyy The magnitude of c G is 8.0m cc c = . (d) The tangent of the angle that c G makes with the + x axis (east) is 3.28 m tan 4.50. 7.29 m y x c c =
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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