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= 0 + 3.28 m = 3.28 m
yy
y
cab
=+
.
The magnitude of
c
is
()
22
2.71m
3.28m
4.2 m.
xy
ccc
=
+
=
(b) The angle
θ
that
G
G
G
makes with the +
x
axis is
11
3.28
tan
tan
50 .
2.71
y
x
c
c
−−
§·
==
=
°
¨¸
©¹
The second possibility (
= 50.4° + 180° = 230.4°) is rejected because it would point in a
direction opposite to
G
c
.
(c) The vector
ba
−
G
G
is found by adding
−
G
G
ab
to
. The result is shown on the diagram to
the right. Let
.
cba
=−
G
GG
The components are
2.29 m 5.00 m
7.29 m,
xxx
=−=
−
−
=
−
and
3.28 m.
yyy
The magnitude of
c
G
is
8.0m
cc
c
=
.
(d) The tangent of the angle
that
c
G
makes with the +
x
axis (east) is
3.28 m
tan
4.50.
7.29 m
y
x
c
c
=
−
−
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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