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(b) Since the
y
axis is in the
xy
plane, and
AB
×
G
G
is perpendicular to that plane, then the
answer is 90.0
°
.
(c) The vector can be simplified as
ˆˆ
ˆ
ˆ
ˆ
ˆ
(
3.00k)
( 5.14i 6.13 j) ( 7.72i 9.20 j 3.00k)
ˆˆˆ
18.39i 15.42 j 94.61k
×+
=
−
+
×
−
−
+
=++
G
G
Its magnitude is
ˆ

(
3.00k) = 97.6.
G
G
The angle between the negative direction of the
y
axis (
ˆ
j
−
) and the direction of the above vector is
1
15.42
cos
99.1 .
97.6
θ
−
−
§·
==
°
¨¸
©¹
53. Noting that the given 130
°
is measured counterclockwise from the +
x
axis, the two
vectors can be written as
ˆ
ˆ
8.00(cos130 i sin130 j)
5.14i 6.13 j
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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