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(a) In unitvector notation, we have
12
ˆˆ
(10 cm)i
and
( 10 cm)j.
rr
==
−
GG
Thus, Eq. 42 gives
21
(1
0
cm
)
i
0
)
j
.
rrr
Δ= − =−
+−
GGG
and the magnitude is given by
22


( 10 cm)
14 cm.
r
Δ= −
=
G
(b) Using Eq. 36, the angle is
1
10 cm
tan
45 or
135 .
θ
−
−
§·
°
−
°
¨¸
−
©¹
We choose
135
−°
since the desired angle is in the third quadrant. In terms of the
magnitudeangle notation, one may write
0
)
i
0
)
j
(
1
4
1
3
5)
.
rr r
→
∠−
°
GG G
(c) In this case, we have
ˆ
( 10 cm)j and
(10 cm)j, and
(20 cm)j.
r
=−
=
Δ=
G
Thus,

2
0
c
m
.
r
G
(d) Using Eq. 36, the angle is given by
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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