ch04-p007

# ch04-p007 - 7. The average velocity is given by Eq. 4-8....

This preview shows page 1. Sign up to view the full content.

The total displacement is 123 ˆˆˆ ˆ (40.0 km)i (15.3 km)i (12.9 km) j (50.0 km)i ˆˆ (5.30 km) i (12.9 km) j. rrrr Δ=Δ+Δ+Δ= + + =+ GGGG The time for the trip is (40.0 + 20.0 + 50.0) min = 110 min, which is equivalent to 1.83 h. Eq. 4-8 then yields avg 5.30 km 12.9 km ˆ ˆ i j = (2.90 km/h)i + (7.01 km/h) j. 1.83 h 1.83 h v §· ¨¸ ©¹ G The magnitude is 22 avg | | (2.90 km/h) (7.01 km/h) 7.59 km/h. v = G (b) The angle is given by 1 7.01 km/h tan 67.5 (north of east), 2.90 km/h θ == ° or 22.5 ° east of due north. 7. The average velocity is given by Eq. 4-8. The total displacement Δ G r is the sum of three displacements, each result of a (constant) velocity during a given time. We use a coordinate system with +
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online