2.00ˆˆˆˆ[2.00(8) 5.00(2)]i + [6.00 7.00(16)] j (6.00i 106 j) mtr==−−=−G(b) Taking the derivative of the given expression produces 23( ) = (6.00 5.00) i 28.0 jvttt−−Gwhere we have written v(t) to emphasize its dependence on time. This becomes, at t= 2.00 s, = (19.0i 224 j) m/s.v−G(c) Differentiating the G()found above, with respect to tproduces 212.0 i 84.0j,tt−which yields 2=(24.0i 336 j) m/sa−Gat t= 2.00 s. (d) The angle of Gv, measured from +x, is either 1224 m/stan85.2 or 94.819.0 m/s−§·−°
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.