ch04-p013 - 13 In parts(b and(c we use Eq 4-10 and Eq 4-16...

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2.00 ˆˆ ˆ ˆ [2.00(8) 5.00(2)]i + [6.00 7.00(16)] j (6.00i 106 j) m t r = =− = G (b) Taking the derivative of the given expression produces 23 ( ) = (6.00 5.00) i 28.0 j vt t t −− G where we have written v ( t ) to emphasize its dependence on time. This becomes, at t = 2.00 s, = (19.0i 224 j) m/s. v G (c) Differentiating the G () found above, with respect to t produces 2 12.0 i 84.0 j, tt which yields 2 =(24.0i 336 j) m/s a G at t = 2.00 s. (d) The angle of G v , measured from + x , is either 1 224 m/s tan 85.2 or 94.8 19.0 m/s §· °
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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