ch04-p014

# ch04-p014 - 14. We adopt a coordinate system with i pointed...

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Since the desired angle is in the second quadrant, we pick 135 ° (45 ° north of due west). Note that the displacement can be written as () o 56.6 135 rrr Δ=− = ° GGG in terms of the magnitude-angle notation. (c) The magnitude of G v avg is simply the magnitude of the displacement divided by the time ( Δ t = 30.0 s). Thus, the average velocity has magnitude (56.6 m)/(30.0 s) = 1.89 m/s. (d) Eq. 4-8 shows that G v avg points in the same direction as Δ G r , i.e, 135 ° ( 45 ° north of due west). (e) Using Eq. 4-15, we have 22 o avg ˆˆ (0.333 m/s )i (0.333 m/s )j. vv a t == + Δ GG G The magnitude of the average acceleration vector is therefore equal to 2 avg | | (0.333 m/s ) (0.333 m/s ) 0.471m/s a =+ = G . (f) The direction of avg a G is 2 1 2 0.333 m/s tan 45 or 135 . θ §· ° ° ¨¸ ©¹ Since the desired angle is now in the first quadrant, we choose 45
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## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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