ch04-p015 - x axis to determine the answer: v x = (8.0 m/s)...

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15. We find t by applying Eq. 2-11 to motion along the y axis (with v y = 0 characterizing y = y max ): 0 = (12 m/s) + ( 2.0 m/s 2 ) t ¡ t = 6.0 s. Then, Eq. 2-11 applies to motion along the
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Unformatted text preview: x axis to determine the answer: v x = (8.0 m/s) + (4.0 m/s 2 )(6.0 s) = 32 m/s. Therefore, the velocity of the cart, when it reaches y = y max , is (32 m/s)i ^ ....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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