where we have used Δx= 12.0 m, vx= 4.00 m/s, and ax= 5.00 m/s2. We use the quadratic formula and find t= 1.53 s. Then, Eq. 2-11 (actually, its analog in two dimensions) applies with this value of t. Therefore, its velocity (when Δx= 12.00 m) is 220ˆˆˆ(4.00 m/s)i (5.00 m/s )(1.53 s)i (7.00 m/s )(1.53 s)j(11.7 m/s)i (10.7 m/s) j.
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