This preview shows page 1. Sign up to view the full content.
where we have used
Δ
x
= 12.0 m,
v
x
= 4.00 m/s, and
a
x
= 5.00 m/s
2
.
We use the
quadratic formula and find
t
= 1.53 s.
Then, Eq. 211 (actually, its analog in two
dimensions) applies with this value of
t
.
Therefore, its velocity (when
Δ
x
= 12.00 m) is
22
0
ˆˆ
ˆ
(4.00 m/s)i
(5.00 m/s )(1.53 s)i
(7.00 m/s )(1.53 s)j
(11.7 m/s)i
(10.7 m/s) j.
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics

Click to edit the document details