ch04-p016 - 1 16. We find t by solving x = x0 + v0 xt + ax...

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where we have used Δ x = 12.0 m, v x = 4.00 m/s, and a x = 5.00 m/s 2 . We use the quadratic formula and find t = 1.53 s. Then, Eq. 2-11 (actually, its analog in two dimensions) applies with this value of t . Therefore, its velocity (when Δ x = 12.00 m) is 22 0 ˆˆ ˆ (4.00 m/s)i (5.00 m/s )(1.53 s)i (7.00 m/s )(1.53 s)j (11.7 m/s)i (10.7 m/s) j.
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