()2ˆˆˆ6.04.0i + 8.0 j6.08.0 idvdatttdtdt==−=−GGin SI units. Specifically, we find the acceleration vector at 3.0 st=to be 26.0 8.0(3.0) i ( 18 m/s )i.−=−(b) The equation is G=−60 80..#bgi=0; we find t= 0.75 s. (c) Since the ycomponent of the velocity, vy= 8.0 m/s, is never zero, the velocity cannot vanish.(d) Since speed is the magnitude of the velocity, we have||vv=G2226.04.08.010tt+=in SI units (m/s). To solve for t, we first square both sides of the above equation, followed by some rearrangement: 226.04.064 100
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.