ch04-p030

ch04-p030 - 30. (a) Since the y-component of the velocity...

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Thus, the speed of the stone when max /2 yy = is 22 2 2 (21.4 m/s) ( 12.7 m/s) 24.9 m/s xy vv v =+ = + = . (c) The percentage difference is 24.9 m/s 21.4 m/s 0.163 16.3% 21.4 m/s == . 30. (a) Since the y -component of the velocity of the stone at the top of its path is zero, its speed is 00 cos (28.0 m/s)cos40.0 21.4 m/s x v v v θ = = = ° = . (b) Using the fact that 0 y v = at the maximum height max y , the amount of time it takes for the stone to reach max y is given by Eq. 4-23: sin 0s i n y v g t t g ¡ = . Substituting the above expression into Eq. 4-22, we find the maximum height to be 2 2 0 0 max 0 0 0 0 sin sin sin 11 (s i n) s i n . 2 v yv t g t v g gg g θθ §· =− =
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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