ch04-p033 - 33. We first find the time it takes for the...

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33. We first find the time it takes for the volleyball to hit the ground. Using Eq. 4-22, we have 2 22 00 0 11 ( sin ) 0 2.30 m ( 20.0 m/s)sin(18.0 ) (9.80 m/s ) yy v t g t t t θ −= ¡ ° which gives 0.30 s t = . Thus, the range of the volleyball is () cos (20.0 m/s)cos18.0 (0.30 s) 5.71 m Rv t == ° = On the other hand, when the angle is changed to 0 8.00 , using the same procedure as shown above, we find 2 0 (
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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