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Then Eq. 421 yields
Δ
x
= (
v
0
cos
θ
0
)
t
= 38.7 m. Thus, using Eq. 48, the player must
have an average velocity of
avg
ˆˆ
(38.7 m) i (55 m)i
ˆ
( 5.8 m/s) i
2.81s
r
v
t
Δ−
==
=
−
Δ
G
G
which means his average speed (assuming he ran in only one direction) is 5.8 m/s.
34. Although we could use Eq. 426 to find where it lands, we choose instead to work
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Work

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