Then Eq. 4-21 yields Δx= (v0cos θ0)t= 38.7 m. Thus, using Eq. 4-8, the player must have an average velocity of avg ˆˆ(38.7 m) i (55 m)iˆ( 5.8 m/s) i2.81srvtΔ−===−ΔGGwhich means his average speed (assuming he ran in only one direction) is 5.8 m/s. 34. Although we could use Eq. 4-26 to find where it lands, we choose instead to work
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.