This preview shows page 1. Sign up to view the full content.
36. (a) Solving the quadratic equation Eq. 422:
2
22
00
0
11
(
sin
)
0 2.160 m
(15.00 m/s)sin(45.00 )
(9.800 m/s )
yy v
t g
t
t
t
θ
−=
−
¡
°
−
the total travel time of the shot in the air is found to be
2.352 s
t
=
. Therefore, the
horizontal distance traveled is
()
cos
(15.00 m/s)cos45.00 (2.352 s)
24.95 m
Rv
t
==
°
=
.
(b) Using the procedure outlined in (a) but for
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details