ch04-p041 - 41. Following the hint, we have the...

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41. Following the hint, we have the time-reversed problem with the ball thrown from the ground, towards the right, at 60° measured counterclockwise from a rightward axis. We see in this time-reversed situation that it is convenient to use the familiar coordinate system with + x as rightward and with positive angles measured counterclockwise. (a) The x -equation (with x 0 = 0 and x = 25.0 m) leads to 25.0 m = ( v 0 cos 60.0°)(1.50 s), so that v 0 = 33.3 m/s. And with y 0 = 0, and y = h > 0 at t = 1.50 s, we have yy v t g t y −= 00 1 2 2 where v 0 y = v 0 sin 60.0°. This leads to h = 32.3 m.
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