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43. (a)
Let
m
=
d
2
d
1
= 0.600 be the slope of the ramp, so
y = mx
there.
We choose our
coordinate origin at the point of launch and use Eq. 425.
Thus,
22
(9.80 m/s )
tan(50.0 )
0.600
2(10.0 m/s) (cos50.0 )
x
y
xx
=°
−
=
°
which yields
x
= 4.99 m.
This is less than
d
1
so the ball
does
land on the ramp.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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