ch04-p044 - 44(a Using the fact that the person(as the...

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(b) The height of the person when he is directly above the second wheel can be found by solving Eq. 4-24. With the second wheel located at 23 m (23/ 2) m 34.5 m, x =+ = we have 22 2 00 2 2 (9.8 m/s )(34.5 m) tan 3.0 m (34.5 m)tan53 2 cos 2(26.52 m/s) (cos53 ) 25.9 m. gx yy x v θ = + ° ° = Therefore, the clearance over the second wheel is 25.9 m 18 m 7.9 m w yyh Δ= − = = . (c) The location of the center of the net is given by 2 2 sin 2 (26.52 m/s) sin(2 53 ) 0t a n 6 9 m . 2 cos 9.8 m/s v gx x vg ⋅° =− = ¡ == = 44. (a) Using the fact that the person (as the projectile) reaches the maximum height over the middle wheel located at 23 m (23/ 2) m
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