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50. From Eq. 421, we find
0
/
x
tx
v
=
. Then Eq. 423 leads to
00
0
.
yy
y
x
gx
vv
g
t
v
v
=−
Since the slope of the graph is
−
0.500, we conclude
g
v
ox
=
1
2
¡
v
ox
= 19.6 m/s.
And from
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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