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60. We apply Eq. 435 to solve for speed
v
and Eq. 434 to find acceleration
a
.
(a) Since the radius of Earth is 6.37
×
10
6
m, the radius of the satellite orbit is
r
= (6.37
×
10
6
+ 640
×
10
3
) m = 7.01
×
10
6
m.
Therefore, the speed of the satellite is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration

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