ch04-p062 - 62. (a) The circumference is c = 2πr =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 62. (a) The circumference is c = 2πr = 2π(0.15 m) = 0.94 m. (b) With T = (60 s)/1200 = 0.050 s, the speed is v = c/T = (0.94 m)/(0.050 s) = 19 m/s. This is equivalent to using Eq. 4-35. (c) The magnitude of the acceleration is a = v2/r = (19 m/s)2/(0.15 m) = 2.4 × 103 m/s2. (d) The period of revolution is (1200 rev/min)–1 = 8.3 × 10–4 min which becomes, in SI units, T = 0.050 s = 50 ms. ...
View Full Document

Ask a homework question - tutors are online