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Unformatted text preview: 62. (a) The circumference is c = 2πr = 2π(0.15 m) = 0.94 m. (b) With T = (60 s)/1200 = 0.050 s, the speed is v = c/T = (0.94 m)/(0.050 s) = 19 m/s. This is equivalent to using Eq. 435. (c) The magnitude of the acceleration is a = v2/r = (19 m/s)2/(0.15 m) = 2.4 × 103 m/s2. (d) The period of revolution is (1200 rev/min)–1 = 8.3 × 10–4 min which becomes, in SI units, T = 0.050 s = 50 ms. ...
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 Spring '08
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 Physics, Acceleration

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