65. We first note thata1→(the acceleration at t1= 2.00 s) is perpendicular to a2→(the acceleration at t2=5.00 s), by taking their scalar (dot) product.:222212ˆˆˆˆ[(6.00 m/s )i+(4.00 m/s )j] [(4.00 m/s )i+( 6.00 m/s )j]=0.aa⋅=⋅−GGSince the acceleration vectors are in the (negative) radial directions, then the two positions (at t1and t2) are a quarter-circle apart (or three-quarters of a circle, depending on whether one measures clockwise or counterclockwise). A quick sketch leads to the conclusion that if the particle is moving counterclockwise (as the problem states) then it
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.