ch04-p068 - 68. We note that after three seconds have...

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68. We note that after three seconds have elapsed ( t 2 t 1 = 3.00 s) the velocity (for this object in circular motion of period T ) is reversed; we infer that it takes three seconds to reach the opposite side of the circle. Thus, T = 2(3.00 s) = 6.00 s. (a) Using Eq. 4-35, r = vT /2 π , where 22 (3.00 m/s) (4.00 m/s) 5.00 m/s v =+ = , we obtain 4.77 m r = . The magnitude of the object’s centripetal acceleration is therefore
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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