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68. We note that after three seconds have elapsed (
t
2
–
t
1
= 3.00 s) the velocity (for this
object in circular motion of period
T
) is reversed; we infer that it takes three seconds to
reach the opposite side of the circle.
Thus,
T
= 2(3.00 s) = 6.00 s.
(a) Using Eq. 435,
r
=
vT
/2
π
, where
22
(3.00 m/s)
(4.00 m/s)
5.00 m/s
v
=+
=
, we obtain
4.77 m
r
=
. The magnitude of the object’s centripetal acceleration is therefore
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Circular Motion

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