ch04-p069 - 69. We use Eq. 4-15 first using velocities...

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c t c g t g ˆˆˆ (12.5 m/s) i ( 5.6 m/s) i (18.1 m/s) i vvv =−= = GGG relative to the truck. Since the velocity of the cheetah relative to the truck at the beginning of the 2.0 s interval is ˆ ( 8.3 m/s)i , the (average) acceleration vector relative to the cameraman (in the truck) is 2 avg ˆˆ (18.1m/s)i ( 8.3 m/s)i ˆ (13 m/s )i, 2.0 s a −− == G or 2 avg || 1 3 m / s . a = G (b) The direction of avg a G is ˆ +i , or eastward. (c) The velocity of the cheetah at the start of the 2.0 s interval is (from Eq. 4-44) 0 cg 0 ct 0 tg ˆ ( 8.3 m/s)i ( 5.6 m/s)i ( 13.9 m/s)i vv v = + =− +− GG G relative to the ground. The (average) acceleration vector relative to the crew member (on
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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