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71. While moving in the same direction as the sidewalk’s motion (covering a distance
d
relative to the ground in time
t
1
= 2.50 s), Eq. 444 leads to
v
sidewalk
+
v
man running
=
d
t
1
.
While he runs back (taking time
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Unformatted text preview: t 2 = 10.0 s) we have v sidewalk − v man running = − d t 2 . Dividing these equations and solving for the desired ratio, we get 12.5 7.5 = 5 3 = 1.67....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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