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,
11
,
1.03 knots
tan
tan
1.5
38.4 knots
AB x
AB y
v
v
θ
−−
§·
==
=
°
¨¸
©¹
which is to say that
G
v
AB
points 1.5° east of north.
(c) Since they started at the same time, their relative velocity describes at what rate the
distance between them is increasing. Because the rate is steady, we have


160
4.2 h.


38.4
AB
AB
r
t
v
Δ
=
G
(d) The velocity
G
v
does not change with time in this problem, and
G
r
is in the same
direction as
G
v
since they started at the same time. Reversing the points of view, we
have
GG
vv
BA
=−
so that
rr
(i.e., they are 180° opposite to each other). Hence,
we conclude that
B
stays at a bearing of 1.5° west of south relative to
A
during the
journey (neglecting the curvature of Earth).
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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