ch04-p082 - 82. We construct a right triangle starting from...

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depends on t and on the boat’s speed (relative to the water), and we set it equal to the Pythagorean “sum” of the triangle’s sides: 4 0 200 82 11 2 2 .. b g b g tt =+ + which leads to a quadratic equation for t 46724 180 4 14 8 0 2 +−= ... We solve this and find a positive value: t = 62.6 s. The angle between the northward (200 m) leg of the triangle and the hypotenuse (which is measured “west of north”) is then given by θ = + F H G I K J = F H G I K J −− tan . tan . 11 82 11 200 151 200 37 t 82. We construct a right triangle starting from the clearing on the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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