ch04-p086 - 86. For circular motion, we must have v with...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
86. For circular motion, we must have v G with direction perpendicular to r and (since the speed is constant) magnitude 2/ vr T π = where 22 (2.00 m) ( 3.00 m) r =+ and 7.00 s T = . The r (given in the problem statement) specifies a point in the fourth quadrant, and since the motion is clockwise then the velocity must have both components
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online