86. For circular motion, we must have vGwith direction perpendicular to r→and (since the speed is constant) magnitude 2/vrTπ=where22(2.00 m)( 3.00 m)r=+−and 7.00 sT=. The r→(given in the problem statement) specifies a point in the fourth quadrant, and since the motion is clockwise then the velocity must have both components
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