ch04-p086 - 86 For circular motion we must have v with...

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86. For circular motion, we must have v G with direction perpendicular to r and (since the speed is constant) magnitude 2/ vr T π = where 22 (2.00 m) ( 3.00 m) r =+ and 7.00 s T = . The r (given in the problem statement) specifies a point in the fourth quadrant, and since the motion is clockwise then the velocity must have both components
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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