86. For circular motion, we must have
v
G
with direction perpendicular to
r
→
and (since
the speed is constant) magnitude
2/
vr
T
π
=
where
22
(2.00 m)
( 3.00 m)
r
=+
−
and
7.00 s
T
=
. The
r
→
(given in the problem statement) specifies a point in the fourth
quadrant, and since the motion is clockwise then the velocity must have both components
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Circular Motion

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