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102. We assume the ball’s initial velocity is perpendicular to the plane of the net. We
choose coordinates so that (
x
0
,
y
0
) = (0, 3.0) m, and
v
x
> 0 (note that
v
0
y
= 0).
(a) To (barely) clear the net, we have
()
22
2
00
11
2.24 m 3.0 m
0
9.8 m/s
y
y
yv
t
g
t
t
−=
−
¡
−
which gives
t
= 0.39 s for the time it is passing over the net. This is plugged into the
x

equation to yield the (minimum) initial velocity
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 Spring '08
 Any
 Physics

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