102. We assume the ball’s initial velocity is perpendicular to the plane of the net. We choose coordinates so that (x0,y0) = (0, 3.0) m, and vx> 0 (note that v0y= 0). (a) To (barely) clear the net, we have ()22200112.24 m 3.0 m09.8 m/syyyvtgtt−=−¡−which gives t= 0.39 s for the time it is passing over the net. This is plugged into the x-equation to yield the (minimum) initial velocity
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