ch04-p104 - 104. We apply Eq. 4-34 to solve for speed v and...

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(a) We obtain vr a == = 50 70 98 19 .. . mm / s m / s . 2 b gb g ch (b) The time to go around once (the period) is T = 2 π r / v = 1.7 s. Therefore, in one minute ( t = 60 s), the astronaut executes 60 s 35 1.7 s t T revolutions. Thus, 35 rev/min is needed to produce a centripetal acceleration of 7
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