105. The radius of Earth may be found in Appendix C. (a) The speed of an object at Earth’s equator is v= 2πR/T, where Ris the radius of Earth (6.37×106m) and Tis the length of a day (8.64 ×104s):v= 2(6.37×106m)/(8.64 ×104s) = 463 m/s. The magnitude of the acceleration is given by avR==×
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.