109. We make use of Eq. 4-25. (a) By rearranging Eq. 4-25, we obtain the initial speed: vxgxy0002=−cos( tan)θθwhich yields v0= 255.5 ≈2.6 ×102m/s for x= 9400 m, y= –3300 m, and θ0= 35°. (b) From Eq. 4-21, we obtain the time of flight:
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.