(b) Adapting Eq. 2-11, the velocity of the particle is given by GGGvv at=+0.Thus, at t= 3.8 s, the velocity is ()22ˆˆˆˆˆ(8.0 m/s) j(4.0 m/s )i(2.0 m/s ) j 3.8 s(15.2 m/s)i(15.6 m/s) jv+=+Gwhich has a magnitude of 22(15.2 m/s)(15.6 m/s)22 m/s.xyvvv=+=111. Since the xand ycomponents of the acceleration are constants, we can use Table 2-1 for the motion along both axes. This can be handled individually (for Δxand Δy) or together with the unit-vector notation (for Δr). Where units are not shown, SI units are to
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