(c) The xcomponent of velocity does not change: vx= v0= 1.00 ×109cm/s = 1.00 ×107m/s. (d) The ycomponent of the velocity is ()()1729861.00 10 cm/s2.00 10 s2.00 10 cm/s2.00 10 m/s.yyvat−==××=×=×113. Since this problem involves constant downward acceleration of magnitude a, similar to the projectile motion situation, we use the equations of §4-6 as long as we substitute aforg. We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The initial velocity is horizontal so that
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