This preview shows page 1. Sign up to view the full content.
()
2
0
2 9.80 m/s
5.00 m
9.90 m/s
y
v
==
(a) Since
v
0
sin
θ
0
=
v
0
y
, with
v
0
= 12.0 m/s, we find
0
= 55.6°.
(b) Now,
v
y
=
v
0
y
–
gt
gives
t
= (9.90 m/s)/(9.80 m/s
2
) = 1.01 s. Thus,
Δ
x
= (
v
0
cos
0
)
t
=
6.85 m.
(c) The velocity at the target has only the
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details