ch04-p118 - 2 118. Since v y = v0 y 2 g y , and vy=0 at the...

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() 2 0 2 9.80 m/s 5.00 m 9.90 m/s y v == (a) Since v 0 sin θ 0 = v 0 y , with v 0 = 12.0 m/s, we find 0 = 55.6°. (b) Now, v y = v 0 y gt gives t = (9.90 m/s)/(9.80 m/s 2 ) = 1.01 s. Thus, Δ x = ( v 0 cos 0 ) t = 6.85 m. (c) The velocity at the target has only the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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