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Because sin
φ
= sin (180° –
), there are two roots of the above equation:
1
0
2
sin (0.218)
12.58 and
167.4 .
θ
−
==
°
°
which correspond to the two possible launch angles that will hit the target (in the absence
of air friction and related effects).
(a) The smallest angle is
0
= 6.29°.
(b) The greatest angle is and
0
= 83.7°.
An alternative approach to this problem in terms of Eq. 425 (with
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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