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129. We denote
G
v
PG
as the velocity of the plane relative to the
ground,
G
v
AG
as the velocity of the air relative to the ground, and
G
v
PA
as the velocity of the plane relative to the air.
(a) The vector diagram is shown on the right:
G
G
G
vvv
PG
PA
AG
=+
.
Since the magnitudes
v
PG
and
v
PA
are equal the triangle is
isosceles, with two sides of equal length.
Consider either of the right triangles formed when the bisector
of
θ
is drawn (the dashed line). It bisects
G
v
, so
()
AG
PG
70.0 mi/h
sin
/ 2
2
2 135 mi/h
v
v
==
which leads to
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 Spring '08
 Any
 Physics

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