ch04-p131 - 131 We make use of Eq 4-24 and Eq 4-25(a With x...

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131. We make use of Eq. 4-24 and Eq. 4-25. (a) With x = 180 m, θ o = 30º, and v o = 43 m/s, we obtain 22 (9.8 m/s )(180 m) tan(30 )(180 m) 11 m 2(43 m/s) (cos30 ) y = ° or | | 11 m y = . This implies the rise is roughly eleven meters above the fairway. (b) The horizontal component (in the absence of air friction) is unchanged, but the
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